x^2-10x-10=0

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Solution for x^2-10x-10=0 equation:


Simplifying
x2 + -10x + -10 = 0

Reorder the terms:
-10 + -10x + x2 = 0

Solving
-10 + -10x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '10' to each side of the equation.
-10 + -10x + 10 + x2 = 0 + 10

Reorder the terms:
-10 + 10 + -10x + x2 = 0 + 10

Combine like terms: -10 + 10 = 0
0 + -10x + x2 = 0 + 10
-10x + x2 = 0 + 10

Combine like terms: 0 + 10 = 10
-10x + x2 = 10

The x term is -10x.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10x + 25 + x2 = 10 + 25

Reorder the terms:
25 + -10x + x2 = 10 + 25

Combine like terms: 10 + 25 = 35
25 + -10x + x2 = 35

Factor a perfect square on the left side:
(x + -5)(x + -5) = 35

Calculate the square root of the right side: 5.916079783

Break this problem into two subproblems by setting 
(x + -5) equal to 5.916079783 and -5.916079783.

Subproblem 1

x + -5 = 5.916079783 Simplifying x + -5 = 5.916079783 Reorder the terms: -5 + x = 5.916079783 Solving -5 + x = 5.916079783 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + x = 5.916079783 + 5 Combine like terms: -5 + 5 = 0 0 + x = 5.916079783 + 5 x = 5.916079783 + 5 Combine like terms: 5.916079783 + 5 = 10.916079783 x = 10.916079783 Simplifying x = 10.916079783

Subproblem 2

x + -5 = -5.916079783 Simplifying x + -5 = -5.916079783 Reorder the terms: -5 + x = -5.916079783 Solving -5 + x = -5.916079783 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + x = -5.916079783 + 5 Combine like terms: -5 + 5 = 0 0 + x = -5.916079783 + 5 x = -5.916079783 + 5 Combine like terms: -5.916079783 + 5 = -0.916079783 x = -0.916079783 Simplifying x = -0.916079783

Solution

The solution to the problem is based on the solutions from the subproblems. x = {10.916079783, -0.916079783}

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